Ronnie Spector Net Worth
Ronnie Spector net worth: Ronnie Spector is an American singer and musician who has a net worth of $5 million dollars. Ronnie Spector, also known as Veronica Yvette Bennett, was born in New York, New York, and began singing as a child. She performed with The Ronettes, which also featured her sister and her cousin.
The group was hugely popular in the sixties, releasing such hit songs as "Be My Baby" and "Baby I Love You". However, their stardom started to fade by the late 60s. Ronnie Spector married Phil Spector who he was reportedly very abusive, and kept her locked in their house. She ultimately left him by breaking through a glass door and walking out, barefoot, since he often hid her shoes so she couldn't leave. After struggling to make a comeback throughout the 70s and early 80s, she finally broke through as the featured vocalist on Eddie Money's hit song, "Take Me Home Tonight". Since then, she has released two critically acclaimed solo albums, and continues to tour and guest-perform with other artists.
|Net Worth:||$5 Million|
|Date of Birth:||Aug 10, 1943 (78 years old)|
|Height:||5 ft 1 in (1.562 m)|
|Nationality:||United States of America|