Rob Gronkowski Net Worth
Rob Gronkowski net worth, career earnings and salary: Rob Gronkowski is an American football player who has a net worth of $40 million dollars. Born in Amherst, New York, Rob Gronkowski excelled at football throughout his high school years, eventually receiving multiple honors his senior year, including being named a PrepStar All-American and an Associated Press Class 4-A All State athlete. He went on to college at the University of Arizona, where he set multiple school records as a tight end, and was named an All-Pac-10 First Team tight end. The New England Patriots drafted him after his sophomore year. As a Patriot, he has set multiple records, including the record for most touchdown receptions by a tight end. He is a five-time Pro-Bowl Champion, and a four-time All-Pro selection. He won three Super Bowls during his career. In 2012, Gronk signed with the Patriots for an additional six seasons. His extension deal, valued at $54 million, was the largest agreement ever made between a team and a tight end in NFL history at the time.
Rob Gronkowski net worth from contracts and endorsements: During his time in the NFL, Gronk earned around $60 million in salary alone. He also earned tens of millions more off the field through endorsements with companies like Tide. Gronk announced his retirement on March 24, 2019 when he was 29 years old. He famously claims to not have spent a dime of his NFL salary and instead lives exclusively off his endorsement deal money. In addition to Tide, Gronk endorses Nike, Dunkin' Donuts, Visa, T-Mobile, Lyft, Cheerios, Monster Energy and more.
|Net Worth:||$40 Million|
|Date of Birth:||May 14, 1989 (31 years old)|
|Height:||6 ft 5 in (1.98 m)|
|Profession:||American football player|
|Nationality:||United States of America|