DeAndre Hopkins Net Worth
DeAndre Hopkins net worth: DeAndre Hopkins is an American professional football player who has a net worth of $40 million. He is best known for being a wide receiver for the NFL's Houston Texans.
DeAndre Hopkins was born in Central, South Carolina in June 1992. He is a wide receiver who played at D.W. Daniel High School. Hopkins played his college football for Clemson where he won the ACC championship in 2011. He was named first-team All-ACC in 2012. Hopkins was drafted #27 overall by the Houston Texans in the 2013 NFL Draft. He was named to the PFWA All-Rookie Team in 2013. Hopkins was the NFL receiving touchdowns leader in 2017. He a second-team All-Pro selection in 2015 and a first-team All-Pro in 2017, 2018, and 2019. Hopkins was selected to the Pro Bowl in 2015, 2017, 2018, and 2019.
Contracts: DeAndre signed a four year deal with the Texans for $7.62 million with $6.18 million guaranteed and a signing bonus of $3.92 million in 2013. Hopkins signed a five year deal with the Texans in 2017 for $81 million with $49 million guaranteed and a signing bonus of $7.5 million.
On September 8, 2020 it was revealed that DeAndre had signed a two-year $54.5 million contract with the Arizona Cardinals. At the time of signing, the contract made DeAndre the highest-paid non-quarterback in NFL history. The deal included $42.75 million in guaranteed money.
|Net Worth:||$40 Million|
|Date of Birth:||Jun 6, 1992 (29 years old)|
|Place of Birth:||Clemson, South Carolina|